Base | Representation |
---|---|
bin | 111000100000010100… |
… | …0011101000111010011 |
3 | 102121012122001222112201 |
4 | 1301000220131013103 |
5 | 3442002404243443 |
6 | 131424442504031 |
7 | 11524001101135 |
oct | 1610050350723 |
9 | 377178058481 |
10 | 121343431123 |
11 | 47509226882 |
12 | 1b625805017 |
13 | b59a61a825 |
14 | 5c31931055 |
15 | 3252dc434d |
hex | 1c40a1d1d3 |
121343431123 has 2 divisors, whose sum is σ = 121343431124. Its totient is φ = 121343431122.
The previous prime is 121343431103. The next prime is 121343431127. The reversal of 121343431123 is 321134343121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121343431123 is a prime.
It is a super-2 number, since 2×1213434311232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121343431091 and 121343431100.
It is not a weakly prime, because it can be changed into another prime (121343431127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60671715561 + 60671715562.
It is an arithmetic number, because the mean of its divisors is an integer number (60671715562).
Almost surely, 2121343431123 is an apocalyptic number.
121343431123 is a deficient number, since it is larger than the sum of its proper divisors (1).
121343431123 is an equidigital number, since it uses as much as digits as its factorization.
121343431123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 28.
Adding to 121343431123 its reverse (321134343121), we get a palindrome (442477774244).
The spelling of 121343431123 in words is "one hundred twenty-one billion, three hundred forty-three million, four hundred thirty-one thousand, one hundred twenty-three".
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