Base | Representation |
---|---|
bin | 111000100000010100… |
… | …0011101000111010111 |
3 | 102121012122001222112212 |
4 | 1301000220131013113 |
5 | 3442002404244002 |
6 | 131424442504035 |
7 | 11524001101142 |
oct | 1610050350727 |
9 | 377178058485 |
10 | 121343431127 |
11 | 47509226886 |
12 | 1b62580501b |
13 | b59a61a829 |
14 | 5c31931059 |
15 | 3252dc4352 |
hex | 1c40a1d1d7 |
121343431127 has 2 divisors, whose sum is σ = 121343431128. Its totient is φ = 121343431126.
The previous prime is 121343431123. The next prime is 121343431169. The reversal of 121343431127 is 721134343121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121343431127 - 22 = 121343431123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121343431093 and 121343431102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121343431123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60671715563 + 60671715564.
It is an arithmetic number, because the mean of its divisors is an integer number (60671715564).
Almost surely, 2121343431127 is an apocalyptic number.
121343431127 is a deficient number, since it is larger than the sum of its proper divisors (1).
121343431127 is an equidigital number, since it uses as much as digits as its factorization.
121343431127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12096, while the sum is 32.
Adding to 121343431127 its reverse (721134343121), we get a palindrome (842477774248).
The spelling of 121343431127 in words is "one hundred twenty-one billion, three hundred forty-three million, four hundred thirty-one thousand, one hundred twenty-seven".
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