Base | Representation |
---|---|
bin | 1011000010010100001010… |
… | …0111110011110011001011 |
3 | 1120222001000020000221112221 |
4 | 2300211002213303303023 |
5 | 3042302222441440433 |
6 | 41450244435514511 |
7 | 2361452516044633 |
oct | 260450247636313 |
9 | 46861006027487 |
10 | 12134400343243 |
11 | 3959196717a42 |
12 | 143b88a158a37 |
13 | 6a03661176c9 |
14 | 2dd4456516c3 |
15 | 16099c23972d |
hex | b09429f3ccb |
12134400343243 has 2 divisors, whose sum is σ = 12134400343244. Its totient is φ = 12134400343242.
The previous prime is 12134400343207. The next prime is 12134400343259. The reversal of 12134400343243 is 34234300443121.
12134400343243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12134400343243 - 217 = 12134400212171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12134400343199 and 12134400343208.
It is not a weakly prime, because it can be changed into another prime (12134400343643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067200171621 + 6067200171622.
It is an arithmetic number, because the mean of its divisors is an integer number (6067200171622).
Almost surely, 212134400343243 is an apocalyptic number.
12134400343243 is a deficient number, since it is larger than the sum of its proper divisors (1).
12134400343243 is an equidigital number, since it uses as much as digits as its factorization.
12134400343243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 12134400343243 its reverse (34234300443121), we get a palindrome (46368700786364).
The spelling of 12134400343243 in words is "twelve trillion, one hundred thirty-four billion, four hundred million, three hundred forty-three thousand, two hundred forty-three".
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