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121344242211053 is a prime number
BaseRepresentation
bin11011100101110010101000…
…011100111101100011101101
3120220122101200212122200012222
4123211302220130331203231
5111401101002001223203
61110024435244405125
734362555304354601
oct3345625034754355
9526571625580188
10121344242211053
1135733893321394
12117393b12467a5
135292936441404
1421d7142389501
15e066976ce038
hex6e5ca873d8ed

121344242211053 has 2 divisors, whose sum is σ = 121344242211054. Its totient is φ = 121344242211052.

The previous prime is 121344242211029. The next prime is 121344242211083. The reversal of 121344242211053 is 350112242443121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100944178221604 + 20400063989449 = 10047098^2 + 4516643^2 .

It is a cyclic number.

It is not a de Polignac number, because 121344242211053 - 28 = 121344242210797 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121344242211083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60672121105526 + 60672121105527.

It is an arithmetic number, because the mean of its divisors is an integer number (60672121105527).

Almost surely, 2121344242211053 is an apocalyptic number.

It is an amenable number.

121344242211053 is a deficient number, since it is larger than the sum of its proper divisors (1).

121344242211053 is an equidigital number, since it uses as much as digits as its factorization.

121344242211053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46080, while the sum is 35.

Adding to 121344242211053 its reverse (350112242443121), we get a palindrome (471456484654174).

The spelling of 121344242211053 in words is "one hundred twenty-one trillion, three hundred forty-four billion, two hundred forty-two million, two hundred eleven thousand, fifty-three".