Base | Representation |
---|---|
bin | 10001101010000111010… |
… | …001001100111111100110 |
3 | 11022000010102122122020121 |
4 | 101222013101030333212 |
5 | 124340121223230202 |
6 | 2325241253152154 |
7 | 153445266420040 |
oct | 21520721147746 |
9 | 4260112578217 |
10 | 1213450211302 |
11 | 4286920119aa |
12 | 17721202b65a |
13 | 8a57402b614 |
14 | 42a349a8a90 |
15 | 2187091d537 |
hex | 11a8744cfe6 |
1213450211302 has 16 divisors (see below), whose sum is σ = 2080413972000. Its totient is φ = 519996688128.
The previous prime is 1213450211287. The next prime is 1213450211327. The reversal of 1213450211302 is 2031120543121.
It is a super-2 number, since 2×12134502113022 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4308843 + ... + 4581814.
It is an arithmetic number, because the mean of its divisors is an integer number (130025873250).
Almost surely, 21213450211302 is an apocalyptic number.
1213450211302 is a deficient number, since it is larger than the sum of its proper divisors (866963760698).
1213450211302 is an equidigital number, since it uses as much as digits as its factorization.
1213450211302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8900415.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1213450211302 its reverse (2031120543121), we get a palindrome (3244570754423).
The spelling of 1213450211302 in words is "one trillion, two hundred thirteen billion, four hundred fifty million, two hundred eleven thousand, three hundred two".
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