Base | Representation |
---|---|
bin | 10110100110100100… |
… | …01000011001011001 |
3 | 1011022200112121210021 |
4 | 23103102020121121 |
5 | 144322434231103 |
6 | 5324040150441 |
7 | 606465036151 |
oct | 132322103131 |
9 | 34280477707 |
10 | 12134680153 |
11 | 516778a892 |
12 | 2427a68421 |
13 | 11b502b61b |
14 | 831879761 |
15 | 4b04c5bbd |
hex | 2d3488659 |
12134680153 has 2 divisors, whose sum is σ = 12134680154. Its totient is φ = 12134680152.
The previous prime is 12134680139. The next prime is 12134680177. The reversal of 12134680153 is 35108643121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10677502224 + 1457177929 = 103332^2 + 38173^2 .
It is a cyclic number.
It is not a de Polignac number, because 12134680153 - 217 = 12134549081 is a prime.
It is a super-2 number, since 2×121346801532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12134650153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067340076 + 6067340077.
It is an arithmetic number, because the mean of its divisors is an integer number (6067340077).
Almost surely, 212134680153 is an apocalyptic number.
It is an amenable number.
12134680153 is a deficient number, since it is larger than the sum of its proper divisors (1).
12134680153 is an equidigital number, since it uses as much as digits as its factorization.
12134680153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 34.
The spelling of 12134680153 in words is "twelve billion, one hundred thirty-four million, six hundred eighty thousand, one hundred fifty-three".
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