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12134763452993 is a prime number
BaseRepresentation
bin1011000010010101100001…
…0000111101101001000001
31120222001221112021211111012
42300211120100331221001
53042303443420443433
641450344450330305
72361464515322636
oct260453020755101
946861845254435
1012134763452993
113959362686745
12143b96b889995
136a03c3410a4c
142dd47b97218d
151609be062848
hexb095843da41

12134763452993 has 2 divisors, whose sum is σ = 12134763452994. Its totient is φ = 12134763452992.

The previous prime is 12134763452969. The next prime is 12134763453017. The reversal of 12134763452993 is 39925436743121.

It is a balanced prime because it is at equal distance from previous prime (12134763452969) and next prime (12134763453017).

It can be written as a sum of positive squares in only one way, i.e., 10458549025024 + 1676214427969 = 3233968^2 + 1294687^2 .

It is a cyclic number.

It is not a de Polignac number, because 12134763452993 - 28 = 12134763452737 is a prime.

It is not a weakly prime, because it can be changed into another prime (12134763452393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067381726496 + 6067381726497.

It is an arithmetic number, because the mean of its divisors is an integer number (6067381726497).

Almost surely, 212134763452993 is an apocalyptic number.

It is an amenable number.

12134763452993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12134763452993 is an equidigital number, since it uses as much as digits as its factorization.

12134763452993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 29393280, while the sum is 59.

The spelling of 12134763452993 in words is "twelve trillion, one hundred thirty-four billion, seven hundred sixty-three million, four hundred fifty-two thousand, nine hundred ninety-three".