Base | Representation |
---|---|
bin | 1011000010010101100001… |
… | …0000111111101001011001 |
3 | 1120222001221112022020202111 |
4 | 2300211120100333221121 |
5 | 3042303443421224314 |
6 | 41450344450432321 |
7 | 2361464515355614 |
oct | 260453020775131 |
9 | 46861845266674 |
10 | 12134763461209 |
11 | 3959362691934 |
12 | 143b96b8926a1 |
13 | 6a03c34146cc |
14 | 2dd47b97517b |
15 | 1609be064ec4 |
hex | b095843fa59 |
12134763461209 has 2 divisors, whose sum is σ = 12134763461210. Its totient is φ = 12134763461208.
The previous prime is 12134763461201. The next prime is 12134763461213. The reversal of 12134763461209 is 90216436743121.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8384065025625 + 3750698435584 = 2895525^2 + 1936672^2 .
It is a cyclic number.
It is not a de Polignac number, because 12134763461209 - 23 = 12134763461201 is a prime.
It is not a weakly prime, because it can be changed into another prime (12134763461201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067381730604 + 6067381730605.
It is an arithmetic number, because the mean of its divisors is an integer number (6067381730605).
Almost surely, 212134763461209 is an apocalyptic number.
It is an amenable number.
12134763461209 is a deficient number, since it is larger than the sum of its proper divisors (1).
12134763461209 is an equidigital number, since it uses as much as digits as its factorization.
12134763461209 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1306368, while the sum is 49.
The spelling of 12134763461209 in words is "twelve trillion, one hundred thirty-four billion, seven hundred sixty-three million, four hundred sixty-one thousand, two hundred nine".
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