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12135253115561 is a prime number
BaseRepresentation
bin1011000010010111010101…
…1100111000001010101001
31120222010012122200021020212
42300211311130320022221
53042310444244144221
641450505221430505
72361512612353412
oct260456534701251
946863178607225
1012135253115561
113959594022454
12143ba8786b435
136a04709b6804
142dd4c69d6809
151609ec037b5b
hexb09757382a9

12135253115561 has 2 divisors, whose sum is σ = 12135253115562. Its totient is φ = 12135253115560.

The previous prime is 12135253115477. The next prime is 12135253115599. The reversal of 12135253115561 is 16551135253121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9143027777536 + 2992225338025 = 3023744^2 + 1729805^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12135253115561 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12135253175561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067626557780 + 6067626557781.

It is an arithmetic number, because the mean of its divisors is an integer number (6067626557781).

Almost surely, 212135253115561 is an apocalyptic number.

It is an amenable number.

12135253115561 is a deficient number, since it is larger than the sum of its proper divisors (1).

12135253115561 is an equidigital number, since it uses as much as digits as its factorization.

12135253115561 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 135000, while the sum is 41.

Adding to 12135253115561 its reverse (16551135253121), we get a palindrome (28686388368682).

The spelling of 12135253115561 in words is "twelve trillion, one hundred thirty-five billion, two hundred fifty-three million, one hundred fifteen thousand, five hundred sixty-one".