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1213534345501 is a prime number
BaseRepresentation
bin10001101010001100010…
…010001001100100011101
311022000100021222002200001
4101222030102021210131
5124340304243024001
62325253500334301
7153450340512202
oct21521422114435
94260307862601
101213534345501
114287255571a5
12177236244391
138a5885a867a
1442a41c29ca9
1521877edc001
hex11a8c48991d

1213534345501 has 2 divisors, whose sum is σ = 1213534345502. Its totient is φ = 1213534345500.

The previous prime is 1213534345487. The next prime is 1213534345519. The reversal of 1213534345501 is 1055434353121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 967270283001 + 246264062500 = 983499^2 + 496250^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213534345501 - 221 = 1213532248349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213534345531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606767172750 + 606767172751.

It is an arithmetic number, because the mean of its divisors is an integer number (606767172751).

Almost surely, 21213534345501 is an apocalyptic number.

It is an amenable number.

1213534345501 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213534345501 is an equidigital number, since it uses as much as digits as its factorization.

1213534345501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108000, while the sum is 37.

Adding to 1213534345501 its reverse (1055434353121), we get a palindrome (2268968698622).

The spelling of 1213534345501 in words is "one trillion, two hundred thirteen billion, five hundred thirty-four million, three hundred forty-five thousand, five hundred one".