Base | Representation |
---|---|
bin | 10001101010001100101… |
… | …000100110011111001101 |
3 | 11022000100201001010012211 |
4 | 101222030220212133031 |
5 | 124340312244343432 |
6 | 2325254230430421 |
7 | 153450441524344 |
oct | 21521450463715 |
9 | 4260321033184 |
10 | 1213540231117 |
11 | 428728907145 |
12 | 177238202411 |
13 | 8a589889596 |
14 | 42a4291cb5b |
15 | 218787a0d47 |
hex | 11a8ca267cd |
1213540231117 has 2 divisors, whose sum is σ = 1213540231118. Its totient is φ = 1213540231116.
The previous prime is 1213540231097. The next prime is 1213540231147. The reversal of 1213540231117 is 7111320453121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 874264270441 + 339275960676 = 935021^2 + 582474^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1213540231117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1213540231147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606770115558 + 606770115559.
It is an arithmetic number, because the mean of its divisors is an integer number (606770115559).
Almost surely, 21213540231117 is an apocalyptic number.
It is an amenable number.
1213540231117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213540231117 is an equidigital number, since it uses as much as digits as its factorization.
1213540231117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 31.
Adding to 1213540231117 its reverse (7111320453121), we get a palindrome (8324860684238).
The spelling of 1213540231117 in words is "one trillion, two hundred thirteen billion, five hundred forty million, two hundred thirty-one thousand, one hundred seventeen".
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