Base | Representation |
---|---|
bin | 10001101010001101001… |
… | …110011100011101111111 |
3 | 11022000101101201010111022 |
4 | 101222031032130131333 |
5 | 124340322314322201 |
6 | 2325255223214355 |
7 | 153450622043033 |
oct | 21521516343577 |
9 | 4260341633438 |
10 | 1213550151551 |
11 | 428733472551 |
12 | 17723b5a73bb |
13 | 8a58b950b6a |
14 | 42a43d821c3 |
15 | 218795b041b |
hex | 11a8d39c77f |
1213550151551 has 2 divisors, whose sum is σ = 1213550151552. Its totient is φ = 1213550151550.
The previous prime is 1213550151371. The next prime is 1213550151557. The reversal of 1213550151551 is 1551510553121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1213550151551 - 218 = 1213549889407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1213550151557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606775075775 + 606775075776.
It is an arithmetic number, because the mean of its divisors is an integer number (606775075776).
Almost surely, 21213550151551 is an apocalyptic number.
1213550151551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213550151551 is an equidigital number, since it uses as much as digits as its factorization.
1213550151551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18750, while the sum is 35.
The spelling of 1213550151551 in words is "one trillion, two hundred thirteen billion, five hundred fifty million, one hundred fifty-one thousand, five hundred fifty-one".
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