Base | Representation |
---|---|
bin | 1011000010100011110101… |
… | …0001101100100101110111 |
3 | 1120222102212022000112102121 |
4 | 2300220331101230211313 |
5 | 3042334331020042032 |
6 | 41452222021420411 |
7 | 2361661651265443 |
oct | 260507521544567 |
9 | 46872768015377 |
10 | 12138605627767 |
11 | 395aa544734a3 |
12 | 144066256a707 |
13 | 6a0886423848 |
14 | 2dd723d61823 |
15 | 160b4650ea97 |
hex | b0a3d46c977 |
12138605627767 has 2 divisors, whose sum is σ = 12138605627768. Its totient is φ = 12138605627766.
The previous prime is 12138605627761. The next prime is 12138605627821. The reversal of 12138605627767 is 76772650683121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12138605627767 - 27 = 12138605627639 is a prime.
It is a super-2 number, since 2×121386056277672 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12138605627761) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6069302813883 + 6069302813884.
It is an arithmetic number, because the mean of its divisors is an integer number (6069302813884).
Almost surely, 212138605627767 is an apocalyptic number.
12138605627767 is a deficient number, since it is larger than the sum of its proper divisors (1).
12138605627767 is an equidigital number, since it uses as much as digits as its factorization.
12138605627767 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 35562240, while the sum is 61.
The spelling of 12138605627767 in words is "twelve trillion, one hundred thirty-eight billion, six hundred five million, six hundred twenty-seven thousand, seven hundred sixty-seven".
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