Base | Representation |
---|---|
bin | 111000100010000000… |
… | …1011100100011100001 |
3 | 102121100121002221021221 |
4 | 1301010001130203201 |
5 | 3442111440022311 |
6 | 131434234015041 |
7 | 11525261433514 |
oct | 1610401344341 |
9 | 377317087257 |
10 | 121400314081 |
11 | 47538348892 |
12 | 1b640877481 |
13 | b5a9345a97 |
14 | 5c392dad7b |
15 | 3257dad671 |
hex | 1c4405c8e1 |
121400314081 has 2 divisors, whose sum is σ = 121400314082. Its totient is φ = 121400314080.
The previous prime is 121400314067. The next prime is 121400314151. The reversal of 121400314081 is 180413004121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 85507117056 + 35893197025 = 292416^2 + 189455^2 .
It is a cyclic number.
It is not a de Polignac number, because 121400314081 - 27 = 121400313953 is a prime.
It is a super-2 number, since 2×1214003140812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121400314001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60700157040 + 60700157041.
It is an arithmetic number, because the mean of its divisors is an integer number (60700157041).
Almost surely, 2121400314081 is an apocalyptic number.
It is an amenable number.
121400314081 is a deficient number, since it is larger than the sum of its proper divisors (1).
121400314081 is an equidigital number, since it uses as much as digits as its factorization.
121400314081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
The spelling of 121400314081 in words is "one hundred twenty-one billion, four hundred million, three hundred fourteen thousand, eighty-one".
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