1214040493 has 2 divisors, whose sum is σ = 1214040494. Its totient is φ = 1214040492.

The previous prime is 1214040461. The next prime is 1214040497. The reversal of 1214040493 is 3940404121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1115693604 + 98346889 = 33402^2 + 9917^2 .

It is an emirp because it is prime and its reverse (3940404121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1214040493 - 2⁵ = 1214040461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1214040497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607020246 + 607020247.

It is an arithmetic number, because the mean of its divisors is an integer number (607020247).

Almost surely, 2^1214040493 is an apocalyptic number.

It is an amenable number.

1214040493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214040493 is an equidigital number, since it uses as much as digits as its factorization.

1214040493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

The square root of 1214040493 is about 34843.0838617939. The cubic root of 1214040493 is about 1066.7870232139.

The spelling of 1214040493 in words is "one billion, two hundred fourteen million, forty thousand, four hundred ninety-three".