Base | Representation |
---|---|
bin | 1011000010101010100011… |
… | …1010001110110000111011 |
3 | 1120222121112010221001122212 |
4 | 2300222220322032300323 |
5 | 3042402030310244421 |
6 | 41453121130005335 |
7 | 2362054466240153 |
oct | 260525072166073 |
9 | 46877463831585 |
10 | 12140411415611 |
11 | 39607a0820646 |
12 | 1440a8727684b |
13 | 6a0ab358c16b |
14 | 2dd855b03763 |
15 | 160beed0ce5b |
hex | b0aa8e8ec3b |
12140411415611 has 2 divisors, whose sum is σ = 12140411415612. Its totient is φ = 12140411415610.
The previous prime is 12140411415553. The next prime is 12140411415631. The reversal of 12140411415611 is 11651411404121.
12140411415611 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12140411415611 - 238 = 11865533508667 is a prime.
It is not a weakly prime, because it can be changed into another prime (12140411415631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070205707805 + 6070205707806.
It is an arithmetic number, because the mean of its divisors is an integer number (6070205707806).
Almost surely, 212140411415611 is an apocalyptic number.
12140411415611 is a deficient number, since it is larger than the sum of its proper divisors (1).
12140411415611 is an equidigital number, since it uses as much as digits as its factorization.
12140411415611 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 32.
Adding to 12140411415611 its reverse (11651411404121), we get a palindrome (23791822819732).
The spelling of 12140411415611 in words is "twelve trillion, one hundred forty billion, four hundred eleven million, four hundred fifteen thousand, six hundred eleven".
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