Base | Representation |
---|---|
bin | 10110100111010001… |
… | …11010001010000111 |
3 | 1011100002202222110001 |
4 | 23103220322022013 |
5 | 144331001314033 |
6 | 5324412142131 |
7 | 606566555245 |
oct | 132350721207 |
9 | 34302688401 |
10 | 12140651143 |
11 | 5170098995 |
12 | 2429a67947 |
13 | 11b633c35a |
14 | 832591795 |
15 | 4b0ca4e7d |
hex | 2d3a3a287 |
12140651143 has 2 divisors, whose sum is σ = 12140651144. Its totient is φ = 12140651142.
The previous prime is 12140651093. The next prime is 12140651153. The reversal of 12140651143 is 34115604121.
12140651143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (34115604121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12140651143 - 29 = 12140650631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12140651153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070325571 + 6070325572.
It is an arithmetic number, because the mean of its divisors is an integer number (6070325572).
Almost surely, 212140651143 is an apocalyptic number.
12140651143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12140651143 is an equidigital number, since it uses as much as digits as its factorization.
12140651143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 28.
The spelling of 12140651143 in words is "twelve billion, one hundred forty million, six hundred fifty-one thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •