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12141020131 is a prime number
BaseRepresentation
bin10110100111010100…
…10100001111100011
31011100010110201121021
423103222110033203
5144331100121011
65324424110311
7606602653102
oct132352241743
934303421537
1012141020131
115170320139
12242a005397
1311b643b2a6
1483264a039
154b0d29471
hex2d3a943e3

12141020131 has 2 divisors, whose sum is σ = 12141020132. Its totient is φ = 12141020130.

The previous prime is 12141020117. The next prime is 12141020147. The reversal of 12141020131 is 13102014121.

It is an a-pointer prime, because the next prime (12141020147) can be obtained adding 12141020131 to its sum of digits (16).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12141020131 - 29 = 12141019619 is a prime.

It is a super-2 number, since 2×121410201312 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12141020831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070510065 + 6070510066.

It is an arithmetic number, because the mean of its divisors is an integer number (6070510066).

Almost surely, 212141020131 is an apocalyptic number.

12141020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12141020131 is an equidigital number, since it uses as much as digits as its factorization.

12141020131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12141020131 its reverse (13102014121), we get a palindrome (25243034252).

The spelling of 12141020131 in words is "twelve billion, one hundred forty-one million, twenty thousand, one hundred thirty-one".