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1214104352441 is a prime number
BaseRepresentation
bin10001101010101110010…
…000100011011010111001
311022001211000112110012012
4101222232100203122321
5124342441203234231
62325430221455305
7153500431502051
oct21525620433271
94261730473165
101214104352441
11428998289912
12177375111535
138a649702496
1442a97806561
15218ad082e2b
hex11aae4236b9

1214104352441 has 2 divisors, whose sum is σ = 1214104352442. Its totient is φ = 1214104352440.

The previous prime is 1214104352429. The next prime is 1214104352467. The reversal of 1214104352441 is 1442534014121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1029007360000 + 185096992441 = 1014400^2 + 430229^2 .

It is an emirp because it is prime and its reverse (1442534014121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1214104352441 - 210 = 1214104351417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1214104352398 and 1214104352407.

It is not a weakly prime, because it can be changed into another prime (1214104382441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607052176220 + 607052176221.

It is an arithmetic number, because the mean of its divisors is an integer number (607052176221).

Almost surely, 21214104352441 is an apocalyptic number.

It is an amenable number.

1214104352441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214104352441 is an equidigital number, since it uses as much as digits as its factorization.

1214104352441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15360, while the sum is 32.

Adding to 1214104352441 its reverse (1442534014121), we get a palindrome (2656638366562).

The spelling of 1214104352441 in words is "one trillion, two hundred fourteen billion, one hundred four million, three hundred fifty-two thousand, four hundred forty-one".