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12141055453 is a prime number
BaseRepresentation
bin10110100111010100…
…11100110111011101
31011100010112112001111
423103222130313131
5144331102233303
65324424542021
7606603161062
oct132352346735
934303475044
1012141055453
11517034472a
12242a021911
1311b64513a7
14832658c69
154b0d34b6d
hex2d3a9cddd

12141055453 has 2 divisors, whose sum is σ = 12141055454. Its totient is φ = 12141055452.

The previous prime is 12141055447. The next prime is 12141055469. The reversal of 12141055453 is 35455014121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11173969849 + 967085604 = 105707^2 + 31098^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12141055453 is a prime.

It is a super-3 number, since 3×121410554533 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12141052453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070527726 + 6070527727.

It is an arithmetic number, because the mean of its divisors is an integer number (6070527727).

Almost surely, 212141055453 is an apocalyptic number.

It is an amenable number.

12141055453 is a deficient number, since it is larger than the sum of its proper divisors (1).

12141055453 is an equidigital number, since it uses as much as digits as its factorization.

12141055453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 12141055453 its reverse (35455014121), we get a palindrome (47596069574).

The spelling of 12141055453 in words is "twelve billion, one hundred forty-one million, fifty-five thousand, four hundred fifty-three".