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12141110213 is a prime number
BaseRepresentation
bin10110100111010101…
…01010001111000101
31011100010122022011122
423103222222033011
5144331111011323
65324430043325
7606603506531
oct132352521705
934303568148
1012141110213
115170381891
12242a049545
1311b64702ab
14832670bc1
154b0d45ec8
hex2d3aaa3c5

12141110213 has 2 divisors, whose sum is σ = 12141110214. Its totient is φ = 12141110212.

The previous prime is 12141110183. The next prime is 12141110221. The reversal of 12141110213 is 31201114121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12107261089 + 33849124 = 110033^2 + 5818^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12141110213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12141110191 and 12141110200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12141110273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070555106 + 6070555107.

It is an arithmetic number, because the mean of its divisors is an integer number (6070555107).

Almost surely, 212141110213 is an apocalyptic number.

It is an amenable number.

12141110213 is a deficient number, since it is larger than the sum of its proper divisors (1).

12141110213 is an equidigital number, since it uses as much as digits as its factorization.

12141110213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 12141110213 its reverse (31201114121), we get a palindrome (43342224334).

The spelling of 12141110213 in words is "twelve billion, one hundred forty-one million, one hundred ten thousand, two hundred thirteen".