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12141135407 is a prime number
BaseRepresentation
bin10110100111010101…
…10000011000101111
31011100010200120201202
423103222300120233
5144331112313112
65324430400115
7606603643142
oct132352603057
934303616652
1012141135407
115170399805
12242a06003b
1311b647b8bb
1483267a059
154b0d4d6c2
hex2d3ab062f

12141135407 has 2 divisors, whose sum is σ = 12141135408. Its totient is φ = 12141135406.

The previous prime is 12141135401. The next prime is 12141135421. The reversal of 12141135407 is 70453114121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12141135407 - 26 = 12141135343 is a prime.

It is a super-2 number, since 2×121411354072 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12141135407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12141135401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070567703 + 6070567704.

It is an arithmetic number, because the mean of its divisors is an integer number (6070567704).

Almost surely, 212141135407 is an apocalyptic number.

12141135407 is a deficient number, since it is larger than the sum of its proper divisors (1).

12141135407 is an equidigital number, since it uses as much as digits as its factorization.

12141135407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 29.

Adding to 12141135407 its reverse (70453114121), we get a palindrome (82594249528).

The spelling of 12141135407 in words is "twelve billion, one hundred forty-one million, one hundred thirty-five thousand, four hundred seven".