Base | Representation |
---|---|
bin | 1011000010101101010000… |
… | …0100100011110010011011 |
3 | 1120222200101121111120022111 |
4 | 2300223110010203302123 |
5 | 3042410021144342301 |
6 | 41453321034333151 |
7 | 2362111441232065 |
oct | 260532404436233 |
9 | 46880347446274 |
10 | 12141135543451 |
11 | 396103254a602 |
12 | 144104988a1b7 |
13 | 6a0b9a5c8785 |
14 | 2dd8c3d5c735 |
15 | 160c43699551 |
hex | b0ad4123c9b |
12141135543451 has 2 divisors, whose sum is σ = 12141135543452. Its totient is φ = 12141135543450.
The previous prime is 12141135543431. The next prime is 12141135543517. The reversal of 12141135543451 is 15434553114121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12141135543451 - 213 = 12141135535259 is a prime.
It is not a weakly prime, because it can be changed into another prime (12141135543401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070567771725 + 6070567771726.
It is an arithmetic number, because the mean of its divisors is an integer number (6070567771726).
Almost surely, 212141135543451 is an apocalyptic number.
12141135543451 is a deficient number, since it is larger than the sum of its proper divisors (1).
12141135543451 is an equidigital number, since it uses as much as digits as its factorization.
12141135543451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 144000, while the sum is 40.
Adding to 12141135543451 its reverse (15434553114121), we get a palindrome (27575688657572).
The spelling of 12141135543451 in words is "twelve trillion, one hundred forty-one billion, one hundred thirty-five million, five hundred forty-three thousand, four hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •