Base | Representation |
---|---|
bin | 1011000010101101111010… |
… | …1001100000111001011111 |
3 | 1120222200211222102110012012 |
4 | 2300223132221200321133 |
5 | 3042410402112044403 |
6 | 41453350414101435 |
7 | 2362116024510134 |
oct | 260533651407137 |
9 | 46880758373165 |
10 | 12141313003103 |
11 | 3961113737679 |
12 | 14410991aa87b |
13 | 6a0bc82c029b |
14 | 2dd8dd75458b |
15 | 160c5404eed8 |
hex | b0adea60e5f |
12141313003103 has 2 divisors, whose sum is σ = 12141313003104. Its totient is φ = 12141313003102.
The previous prime is 12141313003087. The next prime is 12141313003109. The reversal of 12141313003103 is 30130031314121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12141313003103 - 24 = 12141313003087 is a prime.
It is a super-2 number, since 2×121413130031032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12141313003109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070656501551 + 6070656501552.
It is an arithmetic number, because the mean of its divisors is an integer number (6070656501552).
Almost surely, 212141313003103 is an apocalyptic number.
12141313003103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12141313003103 is an equidigital number, since it uses as much as digits as its factorization.
12141313003103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12141313003103 its reverse (30130031314121), we get a palindrome (42271344317224).
The spelling of 12141313003103 in words is "twelve trillion, one hundred forty-one billion, three hundred thirteen million, three thousand, one hundred three".
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