Base | Representation |
---|---|
bin | 10110100111010111… |
… | …10000111111000011 |
3 | 1011100011012000200121 |
4 | 23103223300333003 |
5 | 144331144300003 |
6 | 5324440201111 |
7 | 606606124435 |
oct | 132353607703 |
9 | 34304160617 |
10 | 12141400003 |
11 | 517055a587 |
12 | 242a169197 |
13 | 11b6542175 |
14 | 832708655 |
15 | 4b0da1cbd |
hex | 2d3af0fc3 |
12141400003 has 2 divisors, whose sum is σ = 12141400004. Its totient is φ = 12141400002.
The previous prime is 12141399967. The next prime is 12141400009. The reversal of 12141400003 is 30000414121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12141400003 - 213 = 12141391811 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12141400003.
It is not a weakly prime, because it can be changed into another prime (12141400009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070700001 + 6070700002.
It is an arithmetic number, because the mean of its divisors is an integer number (6070700002).
Almost surely, 212141400003 is an apocalyptic number.
12141400003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12141400003 is an equidigital number, since it uses as much as digits as its factorization.
12141400003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 12141400003 its reverse (30000414121), we get a palindrome (42141814124).
The spelling of 12141400003 in words is "twelve billion, one hundred forty-one million, four hundred thousand, three".
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