1214140141033 has 2 divisors, whose sum is σ = 1214140141034. Its totient is φ = 1214140141032.

The previous prime is 1214140141007. The next prime is 1214140141037. The reversal of 1214140141033 is 3301410414121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 719244774889 + 494895366144 = 848083^2 + 703488^2 .

It is an emirp because it is prime and its reverse (3301410414121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1214140141033 - 2¹³ = 1214140132841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1214140140989 and 1214140141007.

It is not a weakly prime, because it can be changed into another prime (1214140141037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607070070516 + 607070070517.

It is an arithmetic number, because the mean of its divisors is an integer number (607070070517).

Almost surely, 2^{1214140141033} is an apocalyptic number.

It is an amenable number.

1214140141033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214140141033 is an equidigital number, since it uses as much as digits as its factorization.

1214140141033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1214140141033 its reverse (3301410414121), we get a palindrome (4515550555154).

The spelling of 1214140141033 in words is "one trillion, two hundred fourteen billion, one hundred forty million, one hundred forty-one thousand, thirty-three".