Base | Representation |
---|---|
bin | 111000100010011011… |
… | …0111101100110110101 |
3 | 102121101120111200110222 |
4 | 1301010312331212311 |
5 | 3442124032434333 |
6 | 131435454424125 |
7 | 11525521613441 |
oct | 1610466754665 |
9 | 377346450428 |
10 | 121414343093 |
11 | 4754526000a |
12 | 1b645502045 |
13 | b5ac218484 |
14 | 5c3b10d821 |
15 | 3259230298 |
hex | 1c44dbd9b5 |
121414343093 has 2 divisors, whose sum is σ = 121414343094. Its totient is φ = 121414343092.
The previous prime is 121414343053. The next prime is 121414343117. The reversal of 121414343093 is 390343414121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97090197649 + 24324145444 = 311593^2 + 155962^2 .
It is an emirp because it is prime and its reverse (390343414121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121414343093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121414343053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60707171546 + 60707171547.
It is an arithmetic number, because the mean of its divisors is an integer number (60707171547).
Almost surely, 2121414343093 is an apocalyptic number.
It is an amenable number.
121414343093 is a deficient number, since it is larger than the sum of its proper divisors (1).
121414343093 is an equidigital number, since it uses as much as digits as its factorization.
121414343093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 121414343093 in words is "one hundred twenty-one billion, four hundred fourteen million, three hundred forty-three thousand, ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •