Search a number
-
+
12142111451 is a prime number
BaseRepresentation
bin10110100111011100…
…11110101011011011
31011100012112011121112
423103232132223123
5144331340031301
65324503330535
7606615146561
oct132356365333
934305464545
1012142111451
1151709a6058
12242a450a4b
1311b6730c42
14832851a31
154b0e929bb
hex2d3b9eadb

12142111451 has 2 divisors, whose sum is σ = 12142111452. Its totient is φ = 12142111450.

The previous prime is 12142111409. The next prime is 12142111453. The reversal of 12142111451 is 15411124121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12142111451 is a prime.

Together with 12142111453, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12142111453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071055725 + 6071055726.

It is an arithmetic number, because the mean of its divisors is an integer number (6071055726).

Almost surely, 212142111451 is an apocalyptic number.

12142111451 is a deficient number, since it is larger than the sum of its proper divisors (1).

12142111451 is an equidigital number, since it uses as much as digits as its factorization.

12142111451 is an evil number, because the sum of its binary digits is even.

The product of its digits is 320, while the sum is 23.

Adding to 12142111451 its reverse (15411124121), we get a palindrome (27553235572).

The spelling of 12142111451 in words is "twelve billion, one hundred forty-two million, one hundred eleven thousand, four hundred fifty-one".