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121421444332103 is a prime number
BaseRepresentation
bin11011100110111010100010…
…000011101011101001000111
3120220220202222020001202211122
4123212322202003223221013
5111403332104222111403
61110124124054024155
734401260403513656
oct3346724203535107
9526822866052748
10121421444332103
11357635aa969613
121175035804805b
135299cbaa0c546
1421dab876d319d
15e086b5231838
hex6e6ea20eba47

121421444332103 has 2 divisors, whose sum is σ = 121421444332104. Its totient is φ = 121421444332102.

The previous prime is 121421444332057. The next prime is 121421444332157. The reversal of 121421444332103 is 301233444124121.

It is a weak prime.

It is an emirp because it is prime and its reverse (301233444124121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121421444332103 - 220 = 121421443283527 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121421444332163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60710722166051 + 60710722166052.

It is an arithmetic number, because the mean of its divisors is an integer number (60710722166052).

Almost surely, 2121421444332103 is an apocalyptic number.

121421444332103 is a deficient number, since it is larger than the sum of its proper divisors (1).

121421444332103 is an equidigital number, since it uses as much as digits as its factorization.

121421444332103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 121421444332103 its reverse (301233444124121), we get a palindrome (422654888456224).

The spelling of 121421444332103 in words is "one hundred twenty-one trillion, four hundred twenty-one billion, four hundred forty-four million, three hundred thirty-two thousand, one hundred three".