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121423239017 is a prime number
BaseRepresentation
bin111000100010101100…
…0111001011101101001
3102121102012020122101122
41301011120321131221
53442133322122032
6131440413225025
711525660334203
oct1610530713551
9377365218348
10121423239017
114754a286713
121b648492175
13b5b1011632
145c3c387773
153259ddb012
hex1c45639769

121423239017 has 2 divisors, whose sum is σ = 121423239018. Its totient is φ = 121423239016.

The previous prime is 121423239011. The next prime is 121423239019. The reversal of 121423239017 is 710932324121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69473889241 + 51949349776 = 263579^2 + 227924^2 .

It is an emirp because it is prime and its reverse (710932324121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121423239017 - 24 = 121423239001 is a prime.

It is a super-2 number, since 2×1214232390172 (a number of 23 digits) contains 22 as substring.

Together with 121423239019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (121423239011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60711619508 + 60711619509.

It is an arithmetic number, because the mean of its divisors is an integer number (60711619509).

Almost surely, 2121423239017 is an apocalyptic number.

It is an amenable number.

121423239017 is a deficient number, since it is larger than the sum of its proper divisors (1).

121423239017 is an equidigital number, since it uses as much as digits as its factorization.

121423239017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 35.

The spelling of 121423239017 in words is "one hundred twenty-one billion, four hundred twenty-three million, two hundred thirty-nine thousand, seventeen".