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121425431453 is a prime number
BaseRepresentation
bin111000100010110000…
…1010000101110011101
3102121102100101000211222
41301011201100232131
53442134402301303
6131440532223125
711526015065144
oct1610541205635
9377370330758
10121425431453
1147550543947
121b64916aaa5
13b5b15cb531
145c3c79875b
15325a1c0938
hex1c45850b9d

121425431453 has 2 divisors, whose sum is σ = 121425431454. Its totient is φ = 121425431452.

The previous prime is 121425431419. The next prime is 121425431489. The reversal of 121425431453 is 354134524121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83499037444 + 37926394009 = 288962^2 + 194747^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121425431453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121425451453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60712715726 + 60712715727.

It is an arithmetic number, because the mean of its divisors is an integer number (60712715727).

Almost surely, 2121425431453 is an apocalyptic number.

It is an amenable number.

121425431453 is a deficient number, since it is larger than the sum of its proper divisors (1).

121425431453 is an equidigital number, since it uses as much as digits as its factorization.

121425431453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 57600, while the sum is 35.

Adding to 121425431453 its reverse (354134524121), we get a palindrome (475559955574).

The spelling of 121425431453 in words is "one hundred twenty-one billion, four hundred twenty-five million, four hundred thirty-one thousand, four hundred fifty-three".