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12143104001141 is a prime number
BaseRepresentation
bin1011000010110100100101…
…1001101000010001110101
31120222212110210111120121212
42300231021121220101311
53042423034111014031
641454244233251205
72362211302652561
oct260551131502165
946885423446555
1012143104001141
113961952702a43
1214414b8b63b05
136a112237ab39
142dda2d5666a1
15160d0b3cb12b
hexb0b49668475

12143104001141 has 2 divisors, whose sum is σ = 12143104001142. Its totient is φ = 12143104001140.

The previous prime is 12143104001071. The next prime is 12143104001159. The reversal of 12143104001141 is 14110040134121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11496704081041 + 646399920100 = 3390679^2 + 803990^2 .

It is a cyclic number.

It is not a de Polignac number, because 12143104001141 - 214 = 12143103984757 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12143104021141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071552000570 + 6071552000571.

It is an arithmetic number, because the mean of its divisors is an integer number (6071552000571).

Almost surely, 212143104001141 is an apocalyptic number.

It is an amenable number.

12143104001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

12143104001141 is an equidigital number, since it uses as much as digits as its factorization.

12143104001141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 12143104001141 its reverse (14110040134121), we get a palindrome (26253144135262).

The spelling of 12143104001141 in words is "twelve trillion, one hundred forty-three billion, one hundred four million, one thousand, one hundred forty-one".