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12143153333 is a prime number
BaseRepresentation
bin10110100111100100…
…11101000010110101
31011100021111002210202
423103302131002311
5144332121401313
65324541530245
7606630046253
oct132362350265
934307432722
1012143153333
115171547913
12242a873985
1311b6a0723c
14832a435d3
154b10eb558
hex2d3c9d0b5

12143153333 has 2 divisors, whose sum is σ = 12143153334. Its totient is φ = 12143153332.

The previous prime is 12143153317. The next prime is 12143153371. The reversal of 12143153333 is 33335134121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12013694449 + 129458884 = 109607^2 + 11378^2 .

It is a cyclic number.

It is not a de Polignac number, because 12143153333 - 24 = 12143153317 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12143153296 and 12143153305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12143150333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071576666 + 6071576667.

It is an arithmetic number, because the mean of its divisors is an integer number (6071576667).

Almost surely, 212143153333 is an apocalyptic number.

It is an amenable number.

12143153333 is a deficient number, since it is larger than the sum of its proper divisors (1).

12143153333 is an equidigital number, since it uses as much as digits as its factorization.

12143153333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9720, while the sum is 29.

Adding to 12143153333 its reverse (33335134121), we get a palindrome (45478287454).

The spelling of 12143153333 in words is "twelve billion, one hundred forty-three million, one hundred fifty-three thousand, three hundred thirty-three".