12143204011033 has 2 divisors, whose sum is σ = 12143204011034. Its totient is φ = 12143204011032.

The previous prime is 12143204011007. The next prime is 12143204011079. The reversal of 12143204011033 is 33011040234121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10838133105424 + 1305070905609 = 3292132^2 + 1142397^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12143204011033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12143204010989 and 12143204011007.

It is not a weakly prime, because it can be changed into another prime (12143804011033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071602005516 + 6071602005517.

It is an arithmetic number, because the mean of its divisors is an integer number (6071602005517).

Almost surely, 2^{12143204011033} is an apocalyptic number.

It is an amenable number.

12143204011033 is a deficient number, since it is larger than the sum of its proper divisors (1).

12143204011033 is an equidigital number, since it uses as much as digits as its factorization.

12143204011033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 12143204011033 its reverse (33011040234121), we get a palindrome (45154244245154).

The spelling of 12143204011033 in words is "twelve trillion, one hundred forty-three billion, two hundred four million, eleven thousand, thirty-three".