Base | Representation |
---|---|
bin | 10110100111100110… |
… | …00011101000101100 |
3 | 1011100021210010122020 |
4 | 23103303003220230 |
5 | 144332141431104 |
6 | 5324545150140 |
7 | 606631305150 |
oct | 132363035054 |
9 | 34307703566 |
10 | 12143311404 |
11 | 5171645654 |
12 | 242a92b350 |
13 | 11b6a61183 |
14 | 832a85060 |
15 | 4b112d2d9 |
hex | 2d3cc3a2c |
12143311404 has 48 divisors (see below), whose sum is σ = 33498796800. Its totient is φ = 3349878336.
The previous prime is 12143311393. The next prime is 12143311421. The reversal of 12143311404 is 40411334121.
12143311404 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2490034 + ... + 2494905.
It is an arithmetic number, because the mean of its divisors is an integer number (697891600).
Almost surely, 212143311404 is an apocalyptic number.
12143311404 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
12143311404 is an abundant number, since it is smaller than the sum of its proper divisors (21355485396).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12143311404 is a wasteful number, since it uses less digits than its factorization.
12143311404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4984982 (or 4984980 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 12143311404 its reverse (40411334121), we get a palindrome (52554645525).
The spelling of 12143311404 in words is "twelve billion, one hundred forty-three million, three hundred eleven thousand, four hundred four".
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