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12143333413 is a prime number
BaseRepresentation
bin10110100111100110…
…01001000000100101
31011100021211020211101
423103303021000211
5144332143132123
65324545440101
7606631426261
oct132363110045
934307736741
1012143333413
115171660142
12242a940031
1311b6a6b1b3
14832a8d0a1
154b1134aad
hex2d3cc9025

12143333413 has 2 divisors, whose sum is σ = 12143333414. Its totient is φ = 12143333412.

The previous prime is 12143333401. The next prime is 12143333417. The reversal of 12143333413 is 31433334121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9089334244 + 3053999169 = 95338^2 + 55263^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12143333413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12143333417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071666706 + 6071666707.

It is an arithmetic number, because the mean of its divisors is an integer number (6071666707).

Almost surely, 212143333413 is an apocalyptic number.

It is an amenable number.

12143333413 is a deficient number, since it is larger than the sum of its proper divisors (1).

12143333413 is an equidigital number, since it uses as much as digits as its factorization.

12143333413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7776, while the sum is 28.

Adding to 12143333413 its reverse (31433334121), we get a palindrome (43576667534).

It can be divided in two parts, 121433 and 33413, that added together give a triangular number (154846 = T556).

The spelling of 12143333413 in words is "twelve billion, one hundred forty-three million, three hundred thirty-three thousand, four hundred thirteen".