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1214343212161 is a prime number
BaseRepresentation
bin10001101010111100011…
…111101110110010000001
311022002102122222210010111
4101222330133232302001
5124343433330242121
62325510033231321
7153506361665062
oct21527437566201
94262378883114
101214343212161
114290000a3742
12177421102541
138a6870442b1
1442abb422569
15218c40162e1
hex11abc7eec81

1214343212161 has 2 divisors, whose sum is σ = 1214343212162. Its totient is φ = 1214343212160.

The previous prime is 1214343212123. The next prime is 1214343212183. The reversal of 1214343212161 is 1612123434121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 772563649936 + 441779562225 = 878956^2 + 664665^2 .

It is an emirp because it is prime and its reverse (1612123434121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1214343212161 - 233 = 1205753277569 is a prime.

It is an alternating number because its digits alternate between odd and even.

It is not a weakly prime, because it can be changed into another prime (1214343212461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607171606080 + 607171606081.

It is an arithmetic number, because the mean of its divisors is an integer number (607171606081).

Almost surely, 21214343212161 is an apocalyptic number.

It is an amenable number.

1214343212161 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214343212161 is an equidigital number, since it uses as much as digits as its factorization.

1214343212161 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 31.

Adding to 1214343212161 its reverse (1612123434121), we get a palindrome (2826466646282).

The spelling of 1214343212161 in words is "one trillion, two hundred fourteen billion, three hundred forty-three million, two hundred twelve thousand, one hundred sixty-one".