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12143616865493 is a prime number
BaseRepresentation
bin1011000010110110011111…
…1110000011010011010101
31120222220210112112210020212
42300231213332003103111
53042430111404143433
641454411153535205
72362230101146121
oct260554776032325
946886715483225
1012143616865493
113962096156583
121441620874505
136a11a46b8479
142dda7b70a581
15160d3b435d48
hexb0b67f834d5

12143616865493 has 2 divisors, whose sum is σ = 12143616865494. Its totient is φ = 12143616865492.

The previous prime is 12143616865489. The next prime is 12143616865511. The reversal of 12143616865493 is 39456861634121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7791791138884 + 4351825726609 = 2791378^2 + 2086103^2 .

It is a cyclic number.

It is not a de Polignac number, because 12143616865493 - 22 = 12143616865489 is a prime.

It is a super-3 number, since 3×121436168654933 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12143616865403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071808432746 + 6071808432747.

It is an arithmetic number, because the mean of its divisors is an integer number (6071808432747).

Almost surely, 212143616865493 is an apocalyptic number.

It is an amenable number.

12143616865493 is a deficient number, since it is larger than the sum of its proper divisors (1).

12143616865493 is an equidigital number, since it uses as much as digits as its factorization.

12143616865493 is an evil number, because the sum of its binary digits is even.

The product of its digits is 22394880, while the sum is 59.

The spelling of 12143616865493 in words is "twelve trillion, one hundred forty-three billion, six hundred sixteen million, eight hundred sixty-five thousand, four hundred ninety-three".