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1214403000431 is a prime number
BaseRepresentation
bin10001101011000000000…
…011110011100001101111
311022002120211111100012212
4101223000003303201233
5124344044132003211
62325520010521035
7153511016120645
oct21530003634157
94262524440185
101214403000431
1142903091a535
1217743913617b
138a696548a7a
1442ac5347195
15218c93c638b
hex11ac00f386f

1214403000431 has 2 divisors, whose sum is σ = 1214403000432. Its totient is φ = 1214403000430.

The previous prime is 1214403000407. The next prime is 1214403000443. The reversal of 1214403000431 is 1340003044121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1214403000431 - 218 = 1214402738287 is a prime.

It is a super-2 number, since 2×12144030004312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1214403000397 and 1214403000406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1214403000451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607201500215 + 607201500216.

It is an arithmetic number, because the mean of its divisors is an integer number (607201500216).

Almost surely, 21214403000431 is an apocalyptic number.

1214403000431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214403000431 is an equidigital number, since it uses as much as digits as its factorization.

1214403000431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1214403000431 its reverse (1340003044121), we get a palindrome (2554406044552).

The spelling of 1214403000431 in words is "one trillion, two hundred fourteen billion, four hundred three million, four hundred thirty-one", and thus it is an aban number.