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12145103635673 is a prime number
BaseRepresentation
bin1011000010111100000010…
…0101101000010011011001
31121000001122011011112112002
42300233000211220103121
53042441133012320143
641455214504330345
72362311663403061
oct260570045502331
947001564145462
1012145103635673
11396278941aa68
1214419767739b5
136a1380727a38
142ddb7cd683a1
15160dc6c1a5b8
hexb0bc09684d9

12145103635673 has 2 divisors, whose sum is σ = 12145103635674. Its totient is φ = 12145103635672.

The previous prime is 12145103635603. The next prime is 12145103635699. The reversal of 12145103635673 is 37653630154121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11159427968329 + 985675667344 = 3340573^2 + 992812^2 .

It is a cyclic number.

It is not a de Polignac number, because 12145103635673 - 240 = 11045592007897 is a prime.

It is not a weakly prime, because it can be changed into another prime (12145103635603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6072551817836 + 6072551817837.

It is an arithmetic number, because the mean of its divisors is an integer number (6072551817837).

Almost surely, 212145103635673 is an apocalyptic number.

It is an amenable number.

12145103635673 is a deficient number, since it is larger than the sum of its proper divisors (1).

12145103635673 is an equidigital number, since it uses as much as digits as its factorization.

12145103635673 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 47.

Adding to 12145103635673 its reverse (37653630154121), we get a palindrome (49798733789794).

The spelling of 12145103635673 in words is "twelve trillion, one hundred forty-five billion, one hundred three million, six hundred thirty-five thousand, six hundred seventy-three".