Base | Representation |
---|---|
bin | 111000100011100111… |
… | …0010011001010100111 |
3 | 102121111100011020022011 |
4 | 1301013032103022213 |
5 | 3442214211441033 |
6 | 131443433015051 |
7 | 11526513044416 |
oct | 1610716231247 |
9 | 377440136264 |
10 | 121454015143 |
11 | 4756569722a |
12 | 1b656854487 |
13 | b5b74c8966 |
14 | 5c424b947d |
15 | 325c969ccd |
hex | 1c473932a7 |
121454015143 has 2 divisors, whose sum is σ = 121454015144. Its totient is φ = 121454015142.
The previous prime is 121454015069. The next prime is 121454015171. The reversal of 121454015143 is 341510454121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121454015143 - 213 = 121454006951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121454015443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60727007571 + 60727007572.
It is an arithmetic number, because the mean of its divisors is an integer number (60727007572).
Almost surely, 2121454015143 is an apocalyptic number.
121454015143 is a deficient number, since it is larger than the sum of its proper divisors (1).
121454015143 is an equidigital number, since it uses as much as digits as its factorization.
121454015143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 121454015143 its reverse (341510454121), we get a palindrome (462964469264).
The spelling of 121454015143 in words is "one hundred twenty-one billion, four hundred fifty-four million, fifteen thousand, one hundred forty-three".
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