Base | Representation |
---|---|
bin | 1011000010111101010011… |
… | …0101001011001011110111 |
3 | 1121000002111211012222200211 |
4 | 2300233110311023023313 |
5 | 3042442331433130111 |
6 | 41455312315450251 |
7 | 2362323256204012 |
oct | 260572465131367 |
9 | 47002454188624 |
10 | 12145443255031 |
11 | 39629430a5019 |
12 | 1441a50456987 |
13 | 6a1405bb8038 |
14 | 2ddbb20d2379 |
15 | 160de6953521 |
hex | b0bd4d4b2f7 |
12145443255031 has 2 divisors, whose sum is σ = 12145443255032. Its totient is φ = 12145443255030.
The previous prime is 12145443255017. The next prime is 12145443255053. The reversal of 12145443255031 is 13055234454121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12145443255031 - 211 = 12145443252983 is a prime.
It is a super-2 number, since 2×121454432550312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12145443265031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6072721627515 + 6072721627516.
It is an arithmetic number, because the mean of its divisors is an integer number (6072721627516).
Almost surely, 212145443255031 is an apocalyptic number.
12145443255031 is a deficient number, since it is larger than the sum of its proper divisors (1).
12145443255031 is an equidigital number, since it uses as much as digits as its factorization.
12145443255031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288000, while the sum is 40.
The spelling of 12145443255031 in words is "twelve trillion, one hundred forty-five billion, four hundred forty-three million, two hundred fifty-five thousand, thirty-one".
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