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12145443255031 is a prime number
BaseRepresentation
bin1011000010111101010011…
…0101001011001011110111
31121000002111211012222200211
42300233110311023023313
53042442331433130111
641455312315450251
72362323256204012
oct260572465131367
947002454188624
1012145443255031
1139629430a5019
121441a50456987
136a1405bb8038
142ddbb20d2379
15160de6953521
hexb0bd4d4b2f7

12145443255031 has 2 divisors, whose sum is σ = 12145443255032. Its totient is φ = 12145443255030.

The previous prime is 12145443255017. The next prime is 12145443255053. The reversal of 12145443255031 is 13055234454121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12145443255031 - 211 = 12145443252983 is a prime.

It is a super-2 number, since 2×121454432550312 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12145443265031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6072721627515 + 6072721627516.

It is an arithmetic number, because the mean of its divisors is an integer number (6072721627516).

Almost surely, 212145443255031 is an apocalyptic number.

12145443255031 is a deficient number, since it is larger than the sum of its proper divisors (1).

12145443255031 is an equidigital number, since it uses as much as digits as its factorization.

12145443255031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 40.

The spelling of 12145443255031 in words is "twelve trillion, one hundred forty-five billion, four hundred forty-three million, two hundred fifty-five thousand, thirty-one".