Base | Representation |
---|---|
bin | 10001101011010010011… |
… | …100010100100011010001 |
3 | 11022010101022211112021021 |
4 | 101223102130110203101 |
5 | 124400212110321131 |
6 | 2330010345155441 |
7 | 153521452453513 |
oct | 21532234244321 |
9 | 4263338745237 |
10 | 1214711417041 |
11 | 429179a224a1 |
12 | 17750448bb81 |
13 | 8a7154027c5 |
14 | 42b142abbb3 |
15 | 218e64e8e11 |
hex | 11ad27148d1 |
1214711417041 has 2 divisors, whose sum is σ = 1214711417042. Its totient is φ = 1214711417040.
The previous prime is 1214711416973. The next prime is 1214711417113. The reversal of 1214711417041 is 1407141174121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 950391014400 + 264320402641 = 974880^2 + 514121^2 .
It is a cyclic number.
It is not a de Polignac number, because 1214711417041 - 223 = 1214703028433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1214711416988 and 1214711417006.
It is not a weakly prime, because it can be changed into another prime (1214711417341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607355708520 + 607355708521.
It is an arithmetic number, because the mean of its divisors is an integer number (607355708521).
Almost surely, 21214711417041 is an apocalyptic number.
It is an amenable number.
1214711417041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1214711417041 is an equidigital number, since it uses as much as digits as its factorization.
1214711417041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6272, while the sum is 34.
The spelling of 1214711417041 in words is "one trillion, two hundred fourteen billion, seven hundred eleven million, four hundred seventeen thousand, forty-one".
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