Base | Representation |
---|---|
bin | 1011000011010110001110… |
… | …1010010000000011111111 |
3 | 1121000201210010222111001001 |
4 | 2300311203222100003333 |
5 | 3043100032413004412 |
6 | 41502340304231131 |
7 | 2362651135642423 |
oct | 260654352200377 |
9 | 47021703874031 |
10 | 12152134500607 |
11 | 3965767135942 |
12 | 14431b930b4a7 |
13 | 6a1c3124954a |
14 | 300248a3ab83 |
15 | 1611890ce957 |
hex | b0d63a900ff |
12152134500607 has 2 divisors, whose sum is σ = 12152134500608. Its totient is φ = 12152134500606.
The previous prime is 12152134500577. The next prime is 12152134500629. The reversal of 12152134500607 is 70600543125121.
12152134500607 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12152134500607 - 215 = 12152134467839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12152134600607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6076067250303 + 6076067250304.
It is an arithmetic number, because the mean of its divisors is an integer number (6076067250304).
Almost surely, 212152134500607 is an apocalyptic number.
12152134500607 is a deficient number, since it is larger than the sum of its proper divisors (1).
12152134500607 is an equidigital number, since it uses as much as digits as its factorization.
12152134500607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 37.
Adding to 12152134500607 its reverse (70600543125121), we get a palindrome (82752677625728).
The spelling of 12152134500607 in words is "twelve trillion, one hundred fifty-two billion, one hundred thirty-four million, five hundred thousand, six hundred seven".
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