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12153114725173 is a prime number
BaseRepresentation
bin1011000011011001111000…
…0101100000101100110101
31121000211022110110001100121
42300312132011200230311
53043104034332201143
641503021442011541
72363014340501122
oct260663605405465
947024273401317
1012153114725173
11396611a482094
121443431646bb1
136a2059351596
143002dccbb749
151611e51a67ed
hexb0d9e160b35

12153114725173 has 2 divisors, whose sum is σ = 12153114725174. Its totient is φ = 12153114725172.

The previous prime is 12153114725123. The next prime is 12153114725183. The reversal of 12153114725173 is 37152741135121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6298684439524 + 5854430285649 = 2509718^2 + 2419593^2 .

It is a cyclic number.

It is not a de Polignac number, because 12153114725173 - 233 = 12144524790581 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12153114725113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6076557362586 + 6076557362587.

It is an arithmetic number, because the mean of its divisors is an integer number (6076557362587).

Almost surely, 212153114725173 is an apocalyptic number.

It is an amenable number.

12153114725173 is a deficient number, since it is larger than the sum of its proper divisors (1).

12153114725173 is an equidigital number, since it uses as much as digits as its factorization.

12153114725173 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 176400, while the sum is 43.

The spelling of 12153114725173 in words is "twelve trillion, one hundred fifty-three billion, one hundred fourteen million, seven hundred twenty-five thousand, one hundred seventy-three".