12153703 has 2 divisors, whose sum is σ = 12153704. Its totient is φ = 12153702.

The previous prime is 12153679. The next prime is 12153719. The reversal of 12153703 is 30735121.

It is a strong prime.

It is an emirp because it is prime and its reverse (30735121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12153703 - 2²¹ = 10056551 is a prime.

It is a super-2 number, since 2×12153703² = 295424993224418, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12153763) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6076851 + 6076852.

It is an arithmetic number, because the mean of its divisors is an integer number (6076852).

Almost surely, 2^12153703 is an apocalyptic number.

12153703 is a deficient number, since it is larger than the sum of its proper divisors (1).

12153703 is an equidigital number, since it uses as much as digits as its factorization.

12153703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 630, while the sum is 22.

The square root of 12153703 is about 3486.2161436147. The cubic root of 12153703 is about 229.9161824390.

Adding to 12153703 its reverse (30735121), we get a palindrome (42888824).

It can be divided in two parts, 121 and 53703, that added together give a square (53824 = 232²).

The spelling of 12153703 in words is "twelve million, one hundred fifty-three thousand, seven hundred three".