Base | Representation |
---|---|
bin | 111000100110001011… |
… | …1001110011010100111 |
3 | 102121201100101222000202 |
4 | 1301030113032122213 |
5 | 3442403300203223 |
6 | 131500153101115 |
7 | 11531611001063 |
oct | 1611427163247 |
9 | 377640358022 |
10 | 121540241063 |
11 | 475aa33001a |
12 | 1b67b6b779b |
13 | b5cc328b07 |
14 | 5c4db22aa3 |
15 | 32652ed428 |
hex | 1c4c5ce6a7 |
121540241063 has 2 divisors, whose sum is σ = 121540241064. Its totient is φ = 121540241062.
The previous prime is 121540241027. The next prime is 121540241077. The reversal of 121540241063 is 360142045121.
It is a strong prime.
It is an emirp because it is prime and its reverse (360142045121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121540241063 - 210 = 121540240039 is a prime.
It is a super-3 number, since 3×1215402410633 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121540241003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60770120531 + 60770120532.
It is an arithmetic number, because the mean of its divisors is an integer number (60770120532).
Almost surely, 2121540241063 is an apocalyptic number.
121540241063 is a deficient number, since it is larger than the sum of its proper divisors (1).
121540241063 is an equidigital number, since it uses as much as digits as its factorization.
121540241063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 121540241063 its reverse (360142045121), we get a palindrome (481682286184).
The spelling of 121540241063 in words is "one hundred twenty-one billion, five hundred forty million, two hundred forty-one thousand, sixty-three".
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