Base | Representation |
---|---|
bin | 10001101011111100010… |
… | …101101010000010100011 |
3 | 11022012012022110100102111 |
4 | 101223330111222002203 |
5 | 124403132031004443 |
6 | 2330204214500151 |
7 | 153545046126313 |
oct | 21537425520243 |
9 | 4265168410374 |
10 | 1215414313123 |
11 | 4294aa76a74a |
12 | 17767b964657 |
13 | 8a7c7c1714a |
14 | 42b7d79b443 |
15 | 2193808e69d |
hex | 11afc56a0a3 |
1215414313123 has 2 divisors, whose sum is σ = 1215414313124. Its totient is φ = 1215414313122.
The previous prime is 1215414313073. The next prime is 1215414313151. The reversal of 1215414313123 is 3213134145121.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (3213134145121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1215414313123 - 237 = 1077975359651 is a prime.
It is not a weakly prime, because it can be changed into another prime (1215414313723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607707156561 + 607707156562.
It is an arithmetic number, because the mean of its divisors is an integer number (607707156562).
Almost surely, 21215414313123 is an apocalyptic number.
1215414313123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1215414313123 is an equidigital number, since it uses as much as digits as its factorization.
1215414313123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8640, while the sum is 31.
Adding to 1215414313123 its reverse (3213134145121), we get a palindrome (4428548458244).
The spelling of 1215414313123 in words is "one trillion, two hundred fifteen billion, four hundred fourteen million, three hundred thirteen thousand, one hundred twenty-three".
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