Base | Representation |
---|---|
bin | 10001101011111100010… |
… | …101101010001101100111 |
3 | 11022012012022110101101201 |
4 | 101223330111222031213 |
5 | 124403132031020311 |
6 | 2330204214503331 |
7 | 153545046131344 |
oct | 21537425521547 |
9 | 4265168411351 |
10 | 1215414313831 |
11 | 4294aa770233 |
12 | 17767b964b47 |
13 | 8a7c7c17573 |
14 | 42b7d79b7cb |
15 | 2193808e9c1 |
hex | 11afc56a367 |
1215414313831 has 2 divisors, whose sum is σ = 1215414313832. Its totient is φ = 1215414313830.
The previous prime is 1215414313753. The next prime is 1215414313859. The reversal of 1215414313831 is 1383134145121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1215414313831 - 27 = 1215414313703 is a prime.
It is a super-2 number, since 2×12154143138312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1215414313871) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607707156915 + 607707156916.
It is an arithmetic number, because the mean of its divisors is an integer number (607707156916).
Almost surely, 21215414313831 is an apocalyptic number.
1215414313831 is a deficient number, since it is larger than the sum of its proper divisors (1).
1215414313831 is an equidigital number, since it uses as much as digits as its factorization.
1215414313831 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 34560, while the sum is 37.
Adding to 1215414313831 its reverse (1383134145121), we get a palindrome (2598548458952).
The spelling of 1215414313831 in words is "one trillion, two hundred fifteen billion, four hundred fourteen million, three hundred thirteen thousand, eight hundred thirty-one".
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