Base | Representation |
---|---|
bin | 10001101011111110001… |
… | …010111011011111010001 |
3 | 11022012021110022012221212 |
4 | 101223332022323133101 |
5 | 124403212413233231 |
6 | 2330211233425505 |
7 | 153545601336131 |
oct | 21537612733721 |
9 | 4265243265855 |
10 | 1215445055441 |
11 | 429516057921 |
12 | 17768a10b295 |
13 | 8a8013bbc76 |
14 | 42b838c0ac1 |
15 | 2193ab1342b |
hex | 11afe2bb7d1 |
1215445055441 has 2 divisors, whose sum is σ = 1215445055442. Its totient is φ = 1215445055440.
The previous prime is 1215445055413. The next prime is 1215445055443. The reversal of 1215445055441 is 1445505445121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1122919583041 + 92525472400 = 1059679^2 + 304180^2 .
It is a cyclic number.
It is not a de Polignac number, because 1215445055441 - 226 = 1215377946577 is a prime.
Together with 1215445055443, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1215445055443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607722527720 + 607722527721.
It is an arithmetic number, because the mean of its divisors is an integer number (607722527721).
Almost surely, 21215445055441 is an apocalyptic number.
It is an amenable number.
1215445055441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1215445055441 is an equidigital number, since it uses as much as digits as its factorization.
1215445055441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 320000, while the sum is 41.
The spelling of 1215445055441 in words is "one trillion, two hundred fifteen billion, four hundred forty-five million, fifty-five thousand, four hundred forty-one".
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